1210010021111 has 2 divisors, whose sum is σ = 1210010021112. Its totient is φ = 1210010021110.

The previous prime is 1210010021083. The next prime is 1210010021113. The reversal of 1210010021111 is 1111200100121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1210010021111 is a prime.

It is a super-3 number, since 3×1210010021111³ (a number of 37 digits) contains 333 as substring.

Together with 1210010021113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1210010021092 and 1210010021101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210010021113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605005010555 + 605005010556.

It is an arithmetic number, because the mean of its divisors is an integer number (605005010556).

Almost surely, 2^{1210010021111} is an apocalyptic number.

1210010021111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210010021111 is an equidigital number, since it uses as much as digits as its factorization.

1210010021111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1210010021111 its reverse (1111200100121), we get a palindrome (2321210121232).

The spelling of 1210010021111 in words is "one trillion, two hundred ten billion, ten million, twenty-one thousand, one hundred eleven".