1210013043221 has 2 divisors, whose sum is σ = 1210013043222. Its totient is φ = 1210013043220.

The previous prime is 1210013043199. The next prime is 1210013043223. The reversal of 1210013043221 is 1223403100121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 647534043025 + 562479000196 = 804695^2 + 749986^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210013043221 - 2¹⁰ = 1210013042197 is a prime.

It is a super-2 number, since 2×1210013043221² (a number of 25 digits) contains 22 as substring.

Together with 1210013043223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1210013043193 and 1210013043202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210013043223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605006521610 + 605006521611.

It is an arithmetic number, because the mean of its divisors is an integer number (605006521611).

Almost surely, 2^{1210013043221} is an apocalyptic number.

It is an amenable number.

1210013043221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210013043221 is an equidigital number, since it uses as much as digits as its factorization.

1210013043221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1210013043221 its reverse (1223403100121), we get a palindrome (2433416143342).

The spelling of 1210013043221 in words is "one trillion, two hundred ten billion, thirteen million, forty-three thousand, two hundred twenty-one".