Search a number
-
+
12100193557 is a prime number
BaseRepresentation
bin10110100010011101…
…00100110100010101
31011020021122112001221
423101032210310111
5144240122143212
65320405050341
7605565643144
oct132116446425
934207575057
1012100193557
11514a275571
1224183b69b1
1311aab4545a
1482b05d75b
154ac462807
hex2d13a4d15

12100193557 has 2 divisors, whose sum is σ = 12100193558. Its totient is φ = 12100193556.

The previous prime is 12100193549. The next prime is 12100193561. The reversal of 12100193557 is 75539100121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10210900401 + 1889293156 = 101049^2 + 43466^2 .

It is a cyclic number.

It is not a de Polignac number, because 12100193557 - 23 = 12100193549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100193587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050096778 + 6050096779.

It is an arithmetic number, because the mean of its divisors is an integer number (6050096779).

Almost surely, 212100193557 is an apocalyptic number.

It is an amenable number.

12100193557 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100193557 is an equidigital number, since it uses as much as digits as its factorization.

12100193557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9450, while the sum is 34.

Adding to 12100193557 its reverse (75539100121), we get a palindrome (87639293678).

The spelling of 12100193557 in words is "twelve billion, one hundred million, one hundred ninety-three thousand, five hundred fifty-seven".