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12100210220022 = 2317118629511961
BaseRepresentation
bin1011000000010100110010…
…1110110101101111110110
31120211202202110021201200220
42300011030232311233312
53041222212304020042
641422432042515210
72356132326562251
oct260051456655766
946752673251626
1012100210220022
113945741243361
121435127b05b06
1369a077924372
142db920922098
1515eb4a8328ec
hexb014cbb5bf6

12100210220022 has 16 divisors (see below), whose sum is σ = 25623974583792. Its totient is φ = 3796144382720.

The previous prime is 12100210219997. The next prime is 12100210220051. The reversal of 12100210220022 is 22002201200121.

It is a super-3 number, since 3×121002102200223 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12100210219983 and 12100210220010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59314755879 + ... + 59314756082.

It is an arithmetic number, because the mean of its divisors is an integer number (1601498411487).

Almost surely, 212100210220022 is an apocalyptic number.

12100210220022 is an abundant number, since it is smaller than the sum of its proper divisors (13523764363770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12100210220022 is a wasteful number, since it uses less digits than its factorization.

12100210220022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118629511983.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 12100210220022 its reverse (22002201200121), we get a palindrome (34102411420143).

The spelling of 12100210220022 in words is "twelve trillion, one hundred billion, two hundred ten million, two hundred twenty thousand, twenty-two".

Divisors: 1 2 3 6 17 34 51 102 118629511961 237259023922 355888535883 711777071766 2016701703337 4033403406674 6050105110011 12100210220022