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1210021122017 is a prime number
BaseRepresentation
bin10001100110111010111…
…000010000111111100001
311021200021110012212001202
4101212322320100333201
5124311110401401032
62323513120010545
7153264310556141
oct21467270207741
94250243185052
101210021122017
11427192418414
12176615760a55
138a14878c1c6
14427cb3c8921
152171e86bd62
hex119bae10fe1

1210021122017 has 2 divisors, whose sum is σ = 1210021122018. Its totient is φ = 1210021122016.

The previous prime is 1210021121957. The next prime is 1210021122061. The reversal of 1210021122017 is 7102211200121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 770446818001 + 439574304016 = 877751^2 + 663004^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210021122017 - 210 = 1210021120993 is a prime.

It is a super-2 number, since 2×12100211220172 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1210021122017.

It is not a weakly prime, because it can be changed into another prime (1210021122097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605010561008 + 605010561009.

It is an arithmetic number, because the mean of its divisors is an integer number (605010561009).

Almost surely, 21210021122017 is an apocalyptic number.

It is an amenable number.

1210021122017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210021122017 is an equidigital number, since it uses as much as digits as its factorization.

1210021122017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 1210021122017 its reverse (7102211200121), we get a palindrome (8312232322138).

The spelling of 1210021122017 in words is "one trillion, two hundred ten billion, twenty-one million, one hundred twenty-two thousand, seventeen".