121002131320 has 64 divisors (see below), whose sum is σ = 315792391680. Its totient is φ = 40867238016.

The previous prime is 121002131291. The next prime is 121002131353. The reversal of 121002131320 is 23131200121.

It is a junction number, because it is equal to n+sod(n) for n = 121002131294 and 121002131303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3206244 + ... + 3243763.

It is an arithmetic number, because the mean of its divisors is an integer number (4934256120).

Almost surely, 2^121002131320 is an apocalyptic number.

121002131320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

121002131320 is an abundant number, since it is smaller than the sum of its proper divisors (194790260360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121002131320 is a wasteful number, since it uses less digits than its factorization.

121002131320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6450092 (or 6450088 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 121002131320 its reverse (23131200121), we get a palindrome (144133331441).

The spelling of 121002131320 in words is "one hundred twenty-one billion, two million, one hundred thirty-one thousand, three hundred twenty".