12100213624703 has 2 divisors, whose sum is σ = 12100213624704. Its totient is φ = 12100213624702.

The previous prime is 12100213624669. The next prime is 12100213624727. The reversal of 12100213624703 is 30742631200121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12100213624703 - 2¹⁴ = 12100213608319 is a prime.

It is a super-2 number, since 2×12100213624703² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12100213624703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100213624783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050106812351 + 6050106812352.

It is an arithmetic number, because the mean of its divisors is an integer number (6050106812352).

Almost surely, 2^{12100213624703} is an apocalyptic number.

12100213624703 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100213624703 is an equidigital number, since it uses as much as digits as its factorization.

12100213624703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 12100213624703 its reverse (30742631200121), we get a palindrome (42842844824824).

The spelling of 12100213624703 in words is "twelve trillion, one hundred billion, two hundred thirteen million, six hundred twenty-four thousand, seven hundred three".