121003111120130 has 32 divisors (see below), whose sum is σ = 240644550409344. Its totient is φ = 43573498836736.

The previous prime is 121003111120121. The next prime is 121003111120139. The reversal of 121003111120130 is 31021111300121.

It is an interprime number because it is at equal distance from previous prime (121003111120121) and next prime (121003111120139).

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a junction number, because it is equal to n+sod(n) for n = 121003111120099 and 121003111120108.

It is not an unprimeable number, because it can be changed into a prime (121003111120139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15473539712 + ... + 15473547531.

It is an arithmetic number, because the mean of its divisors is an integer number (7520142200292).

Almost surely, 2^{121003111120130} is an apocalyptic number.

121003111120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

121003111120130 is a deficient number, since it is larger than the sum of its proper divisors (119641439289214).

121003111120130 is a wasteful number, since it uses less digits than its factorization.

121003111120130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30947087290.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 121003111120130 its reverse (31021111300121), we get a palindrome (152024222420251).

The spelling of 121003111120130 in words is "one hundred twenty-one trillion, three billion, one hundred eleven million, one hundred twenty thousand, one hundred thirty".