12101012113 has 2 divisors, whose sum is σ = 12101012114. Its totient is φ = 12101012112.

The previous prime is 12101012111. The next prime is 12101012129. The reversal of 12101012113 is 31121010121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9360175504 + 2740836609 = 96748^2 + 52353^2 .

It is a cyclic number.

It is not a de Polignac number, because 12101012113 - 2¹ = 12101012111 is a prime.

Together with 12101012111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12101012093 and 12101012102.

It is not a weakly prime, because it can be changed into another prime (12101012111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050506056 + 6050506057.

It is an arithmetic number, because the mean of its divisors is an integer number (6050506057).

Almost surely, 2^12101012113 is an apocalyptic number.

It is an amenable number.

12101012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101012113 is an equidigital number, since it uses as much as digits as its factorization.

12101012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 12101012113 its reverse (31121010121), we get a palindrome (43222022234).

The spelling of 12101012113 in words is "twelve billion, one hundred one million, twelve thousand, one hundred thirteen".