12101040013 has 2 divisors, whose sum is σ = 12101040014. Its totient is φ = 12101040012.

The previous prime is 12101039963. The next prime is 12101040019. The reversal of 12101040013 is 31004010121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8863657609 + 3237382404 = 94147^2 + 56898^2 .

It is a cyclic number.

It is not a de Polignac number, because 12101040013 - 2²¹ = 12098942861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12101039975 and 12101040002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12101040019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050520006 + 6050520007.

It is an arithmetic number, because the mean of its divisors is an integer number (6050520007).

Almost surely, 2^12101040013 is an apocalyptic number.

It is an amenable number.

12101040013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101040013 is an equidigital number, since it uses as much as digits as its factorization.

12101040013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12101040013 its reverse (31004010121), we get a palindrome (43105050134).

The spelling of 12101040013 in words is "twelve billion, one hundred one million, forty thousand, thirteen".