Base | Representation |
---|---|
bin | 11011100000111100010001… |
… | …101010110011111010010111 |
3 | 120212110112112122122100212111 |
4 | 123200330101222303322113 |
5 | 111330121012000001101 |
6 | 1105211404055331451 |
7 | 34326520250326402 |
oct | 3340742152637227 |
9 | 525415478570774 |
10 | 121011000000151 |
11 | 35615527828018 |
12 | 116a48ab080b87 |
13 | 526a39961cc31 |
14 | 21c4d6c386d39 |
15 | decb9195b251 |
hex | 6e0f11ab3e97 |
121011000000151 has 2 divisors, whose sum is σ = 121011000000152. Its totient is φ = 121011000000150.
The previous prime is 121011000000097. The next prime is 121011000000167. The reversal of 121011000000151 is 151000000110121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121011000000151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121011000007151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60505500000075 + 60505500000076.
It is an arithmetic number, because the mean of its divisors is an integer number (60505500000076).
Almost surely, 2121011000000151 is an apocalyptic number.
121011000000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
121011000000151 is an equidigital number, since it uses as much as digits as its factorization.
121011000000151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10, while the sum is 13.
Adding to 121011000000151 its reverse (151000000110121), we get a palindrome (272011000110272).
The spelling of 121011000000151 in words is "one hundred twenty-one trillion, eleven billion, one hundred fifty-one", and thus it is an aban number.
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