Search a number
-
+
121020012120120 = 233517618921435099
BaseRepresentation
bin11011100001000100101010…
…110101010100100000111000
3120212111101210201112111100120
4123201010222311110200320
5111330242441100320440
61105215454232333240
734330256501146551
oct3341045265244070
9525441721474316
10121020012120120
1135619331947153
12116a65a5244220
13526b1a47549b9
1421c5585235328
15ded01cc2ddd0
hex6e112ad54838

121020012120120 has 512 divisors, whose sum is σ = 395370408960000. Its totient is φ = 29520464117760.

The previous prime is 121020012120107. The next prime is 121020012120169. The reversal of 121020012120120 is 21021210020121.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 121020012120120.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 23734065331 + ... + 23734070429.

It is an arithmetic number, because the mean of its divisors is an integer number (772207830000).

Almost surely, 2121020012120120 is an apocalyptic number.

121020012120120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121020012120120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (197685204480000).

121020012120120 is an abundant number, since it is smaller than the sum of its proper divisors (274350396839880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121020012120120 is a wasteful number, since it uses less digits than its factorization.

121020012120120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7423 (or 7419 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 121020012120120 its reverse (21021210020121), we get a palindrome (142041222140241).

The spelling of 121020012120120 in words is "one hundred twenty-one trillion, twenty billion, twelve million, one hundred twenty thousand, one hundred twenty".