Base | Representation |
---|---|
bin | 10001100111000101100… |
… | …011011011111010100111 |
3 | 11021200201221012112010011 |
4 | 101213011203123322213 |
5 | 124311442223223421 |
6 | 2323542554311051 |
7 | 153301614031603 |
oct | 21470543337247 |
9 | 4250657175104 |
10 | 1210200211111 |
11 | 427274518731 |
12 | 176665728487 |
13 | 8a176904598 |
14 | 428070c6503 |
15 | 217304454e1 |
hex | 119c58dbea7 |
1210200211111 has 2 divisors, whose sum is σ = 1210200211112. Its totient is φ = 1210200211110.
The previous prime is 1210200210949. The next prime is 1210200211123. The reversal of 1210200211111 is 1111120020121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1210200211111 - 213 = 1210200202919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1210200211091 and 1210200211100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210200211511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605100105555 + 605100105556.
It is an arithmetic number, because the mean of its divisors is an integer number (605100105556).
Almost surely, 21210200211111 is an apocalyptic number.
1210200211111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210200211111 is an equidigital number, since it uses as much as digits as its factorization.
1210200211111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1210200211111 its reverse (1111120020121), we get a palindrome (2321320231232).
The spelling of 1210200211111 in words is "one trillion, two hundred ten billion, two hundred million, two hundred eleven thousand, one hundred eleven".
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