Base | Representation |
---|---|
bin | 1011000000011011100010… |
… | …1110101100011001010111 |
3 | 1120211221102201200211122021 |
4 | 2300012320232230121113 |
5 | 3041234420130333142 |
6 | 41423331530114011 |
7 | 2356225250514445 |
oct | 260067056543127 |
9 | 46757381624567 |
10 | 12102022121047 |
11 | 3946490a96421 |
12 | 143555287b907 |
13 | 69a2a6120351 |
14 | 2dba53415b95 |
15 | 15ec0493c267 |
hex | b01b8bac657 |
12102022121047 has 2 divisors, whose sum is σ = 12102022121048. Its totient is φ = 12102022121046.
The previous prime is 12102022121041. The next prime is 12102022121153. The reversal of 12102022121047 is 74012122020121.
12102022121047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12102022121047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12102022121041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051011060523 + 6051011060524.
It is an arithmetic number, because the mean of its divisors is an integer number (6051011060524).
Almost surely, 212102022121047 is an apocalyptic number.
12102022121047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12102022121047 is an equidigital number, since it uses as much as digits as its factorization.
12102022121047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 12102022121047 its reverse (74012122020121), we get a palindrome (86114144141168).
The spelling of 12102022121047 in words is "twelve trillion, one hundred two billion, twenty-two million, one hundred twenty-one thousand, forty-seven".
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