Base | Representation |
---|---|
bin | 11011100001000101110010… |
… | …011010110001011001101111 |
3 | 120212111111220102102121121201 |
4 | 123201011302122301121233 |
5 | 111330302421024320421 |
6 | 1105220213334110331 |
7 | 34330331323401343 |
oct | 3341056232613157 |
9 | 525444812377551 |
10 | 121021213120111 |
11 | 35619898876227 |
12 | 116a687b4ab3a7 |
13 | 526b336509395 |
14 | 21c565a945623 |
15 | ded08d3b5b91 |
hex | 6e11726b166f |
121021213120111 has 2 divisors, whose sum is σ = 121021213120112. Its totient is φ = 121021213120110.
The previous prime is 121021213120109. The next prime is 121021213120133. The reversal of 121021213120111 is 111021312120121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121021213120111 - 21 = 121021213120109 is a prime.
It is a super-2 number, since 2×1210212131201112 (a number of 29 digits) contains 22 as substring.
Together with 121021213120109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121021213120151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510606560055 + 60510606560056.
It is an arithmetic number, because the mean of its divisors is an integer number (60510606560056).
Almost surely, 2121021213120111 is an apocalyptic number.
121021213120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
121021213120111 is an equidigital number, since it uses as much as digits as its factorization.
121021213120111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 121021213120111 its reverse (111021312120121), we get a palindrome (232042525240232).
The spelling of 121021213120111 in words is "one hundred twenty-one trillion, twenty-one billion, two hundred thirteen million, one hundred twenty thousand, one hundred eleven".
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