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12102229567853 is a prime number
BaseRepresentation
bin1011000000011100010100…
…0110000010100101101101
31120211221222012001020011022
42300013011012002211231
53041240331232132403
641423404300303525
72356233350005565
oct260070506024555
946757865036138
1012102229567853
1139465880a5267
1214355b0241ba5
1369a30a0b4039
142dba72bb5da5
1515ec17c67d38
hexb01c518296d

12102229567853 has 2 divisors, whose sum is σ = 12102229567854. Its totient is φ = 12102229567852.

The previous prime is 12102229567807. The next prime is 12102229567877. The reversal of 12102229567853 is 35876592220121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11205803115049 + 896426452804 = 3347507^2 + 946798^2 .

It is a cyclic number.

It is not a de Polignac number, because 12102229567853 - 222 = 12102225373549 is a prime.

It is a super-2 number, since 2×121022295678532 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12102229567795 and 12102229567804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12102229597853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051114783926 + 6051114783927.

It is an arithmetic number, because the mean of its divisors is an integer number (6051114783927).

Almost surely, 212102229567853 is an apocalyptic number.

It is an amenable number.

12102229567853 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102229567853 is an equidigital number, since it uses as much as digits as its factorization.

12102229567853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 53.

The spelling of 12102229567853 in words is "twelve trillion, one hundred two billion, two hundred twenty-nine million, five hundred sixty-seven thousand, eight hundred fifty-three".