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1210234311331 is a prime number
BaseRepresentation
bin10001100111000111100…
…101100001001010100011
311021200211022100222211021
4101213013211201022203
5124312024440430311
62323550213230311
7153302506625263
oct21470745411243
94250738328737
101210234311331
11427291799731
12176675032397
138a1809b3926
144280b8417a3
152173342e171
hex119c79612a3

1210234311331 has 2 divisors, whose sum is σ = 1210234311332. Its totient is φ = 1210234311330.

The previous prime is 1210234311329. The next prime is 1210234311337. The reversal of 1210234311331 is 1331134320121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1210234311331 - 21 = 1210234311329 is a prime.

It is a super-2 number, since 2×12102343113312 (a number of 25 digits) contains 22 as substring.

Together with 1210234311329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1210234311296 and 1210234311305.

It is not a weakly prime, because it can be changed into another prime (1210234311337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605117155665 + 605117155666.

It is an arithmetic number, because the mean of its divisors is an integer number (605117155666).

Almost surely, 21210234311331 is an apocalyptic number.

1210234311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210234311331 is an equidigital number, since it uses as much as digits as its factorization.

1210234311331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1210234311331 its reverse (1331134320121), we get a palindrome (2541368631452).

The spelling of 1210234311331 in words is "one trillion, two hundred ten billion, two hundred thirty-four million, three hundred eleven thousand, three hundred thirty-one".