Base | Representation |
---|---|
bin | 11011100001001110010001… |
… | …111101110011000100000111 |
3 | 120212112101102221211111012021 |
4 | 123201032101331303010013 |
5 | 111330430110034031442 |
6 | 1105224322254304011 |
7 | 34331103314403664 |
oct | 3341162175630407 |
9 | 525471387744167 |
10 | 121030332330247 |
11 | 3562274838982a |
12 | 116a85a54b8007 |
13 | 526c15a897c02 |
14 | 21c5c83b0ca6b |
15 | ded423c8de67 |
hex | 6e1391f73107 |
121030332330247 has 2 divisors, whose sum is σ = 121030332330248. Its totient is φ = 121030332330246.
The previous prime is 121030332330161. The next prime is 121030332330253. The reversal of 121030332330247 is 742033233030121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121030332330247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121030332331247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60515166165123 + 60515166165124.
It is an arithmetic number, because the mean of its divisors is an integer number (60515166165124).
Almost surely, 2121030332330247 is an apocalyptic number.
121030332330247 is a deficient number, since it is larger than the sum of its proper divisors (1).
121030332330247 is an equidigital number, since it uses as much as digits as its factorization.
121030332330247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 34.
Adding to 121030332330247 its reverse (742033233030121), we get a palindrome (863063565360368).
The spelling of 121030332330247 in words is "one hundred twenty-one trillion, thirty billion, three hundred thirty-two million, three hundred thirty thousand, two hundred forty-seven".
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