Base | Representation |
---|---|
bin | 10110100010110101… |
… | …11110011100000111 |
3 | 1011020111202200011021 |
4 | 23101122332130013 |
5 | 144241440203411 |
6 | 5321002452011 |
7 | 605635402264 |
oct | 132132763407 |
9 | 34214680137 |
10 | 12103444231 |
11 | 515109587a |
12 | 2419504007 |
13 | 11ab712c28 |
14 | 82b66826b |
15 | 4ac8a5a71 |
hex | 2d16be707 |
12103444231 has 2 divisors, whose sum is σ = 12103444232. Its totient is φ = 12103444230.
The previous prime is 12103444189. The next prime is 12103444247. The reversal of 12103444231 is 13244430121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12103444231 - 29 = 12103443719 is a prime.
It is a super-2 number, since 2×121034442312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12103444196 and 12103444205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12103444291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051722115 + 6051722116.
It is an arithmetic number, because the mean of its divisors is an integer number (6051722116).
Almost surely, 212103444231 is an apocalyptic number.
12103444231 is a deficient number, since it is larger than the sum of its proper divisors (1).
12103444231 is an equidigital number, since it uses as much as digits as its factorization.
12103444231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12103444231 its reverse (13244430121), we get a palindrome (25347874352).
The spelling of 12103444231 in words is "twelve billion, one hundred three million, four hundred forty-four thousand, two hundred thirty-one".
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