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12103444231 is a prime number
BaseRepresentation
bin10110100010110101…
…11110011100000111
31011020111202200011021
423101122332130013
5144241440203411
65321002452011
7605635402264
oct132132763407
934214680137
1012103444231
11515109587a
122419504007
1311ab712c28
1482b66826b
154ac8a5a71
hex2d16be707

12103444231 has 2 divisors, whose sum is σ = 12103444232. Its totient is φ = 12103444230.

The previous prime is 12103444189. The next prime is 12103444247. The reversal of 12103444231 is 13244430121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12103444231 - 29 = 12103443719 is a prime.

It is a super-2 number, since 2×121034442312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12103444196 and 12103444205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12103444291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051722115 + 6051722116.

It is an arithmetic number, because the mean of its divisors is an integer number (6051722116).

Almost surely, 212103444231 is an apocalyptic number.

12103444231 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103444231 is an equidigital number, since it uses as much as digits as its factorization.

12103444231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12103444231 its reverse (13244430121), we get a palindrome (25347874352).

The spelling of 12103444231 in words is "twelve billion, one hundred three million, four hundred forty-four thousand, two hundred thirty-one".