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12104120433397 is a prime number
BaseRepresentation
bin1011000000100011010111…
…0011000111101011110101
31120212010211222001011001111
42300020311303013223311
53041303214312332042
641424320044155021
72356331250052246
oct260106563075365
946763758034044
1012104120433397
113947368481563
121435a39538a71
1369a54ba69ca5
142dbbb1d82ccd
1515ecc8c6e517
hexb0235cc7af5

12104120433397 has 2 divisors, whose sum is σ = 12104120433398. Its totient is φ = 12104120433396.

The previous prime is 12104120433371. The next prime is 12104120433463. The reversal of 12104120433397 is 79333402140121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6204851830116 + 5899268603281 = 2490954^2 + 2428841^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12104120433397 is a prime.

It is a super-2 number, since 2×121041204333972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12104120433347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052060216698 + 6052060216699.

It is an arithmetic number, because the mean of its divisors is an integer number (6052060216699).

Almost surely, 212104120433397 is an apocalyptic number.

It is an amenable number.

12104120433397 is a deficient number, since it is larger than the sum of its proper divisors (1).

12104120433397 is an equidigital number, since it uses as much as digits as its factorization.

12104120433397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 12104120433397 in words is "twelve trillion, one hundred four billion, one hundred twenty million, four hundred thirty-three thousand, three hundred ninety-seven".