Base | Representation |
---|---|
bin | 1011000000100011010111… |
… | …0011000111101100110111 |
3 | 1120212010211222001011010221 |
4 | 2300020311303013230313 |
5 | 3041303214312332323 |
6 | 41424320044155211 |
7 | 2356331250052402 |
oct | 260106563075467 |
9 | 46763758034127 |
10 | 12104120433463 |
11 | 3947368481613 |
12 | 1435a39538b07 |
13 | 69a54ba6a026 |
14 | 2dbbb1d82d39 |
15 | 15ecc8c6e55d |
hex | b0235cc7b37 |
12104120433463 has 2 divisors, whose sum is σ = 12104120433464. Its totient is φ = 12104120433462.
The previous prime is 12104120433397. The next prime is 12104120433473. The reversal of 12104120433463 is 36433402140121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12104120433463 - 29 = 12104120432951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12104120433473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052060216731 + 6052060216732.
It is an arithmetic number, because the mean of its divisors is an integer number (6052060216732).
Almost surely, 212104120433463 is an apocalyptic number.
12104120433463 is a deficient number, since it is larger than the sum of its proper divisors (1).
12104120433463 is an equidigital number, since it uses as much as digits as its factorization.
12104120433463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 12104120433463 its reverse (36433402140121), we get a palindrome (48537522573584).
The spelling of 12104120433463 in words is "twelve trillion, one hundred four billion, one hundred twenty million, four hundred thirty-three thousand, four hundred sixty-three".
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