Base | Representation |
---|---|
bin | 10001100111010011011… |
… | …001001111100110000111 |
3 | 11021201100010010222010221 |
4 | 101213103121033212013 |
5 | 124312431144421411 |
6 | 2324022011325211 |
7 | 153310433545246 |
oct | 21472331174607 |
9 | 4251303128127 |
10 | 1210432420231 |
11 | 4273835aa8a1 |
12 | 17670b450807 |
13 | 8a1b2a58228 |
14 | 42829c9095d |
15 | 21745a13071 |
hex | 119d364f987 |
1210432420231 has 2 divisors, whose sum is σ = 1210432420232. Its totient is φ = 1210432420230.
The previous prime is 1210432420157. The next prime is 1210432420271. The reversal of 1210432420231 is 1320242340121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1210432420231 - 27 = 1210432420103 is a prime.
It is a super-2 number, since 2×12104324202312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1210432420196 and 1210432420205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210432420271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605216210115 + 605216210116.
It is an arithmetic number, because the mean of its divisors is an integer number (605216210116).
Almost surely, 21210432420231 is an apocalyptic number.
1210432420231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210432420231 is an equidigital number, since it uses as much as digits as its factorization.
1210432420231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1210432420231 its reverse (1320242340121), we get a palindrome (2530674760352).
The spelling of 1210432420231 in words is "one trillion, two hundred ten billion, four hundred thirty-two million, four hundred twenty thousand, two hundred thirty-one".
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