Base | Representation |
---|---|
bin | 111000010111011001… |
… | …1001000110110100111 |
3 | 102120102210002120222211 |
4 | 1300232303020312213 |
5 | 3440344311214311 |
6 | 131335034104251 |
7 | 11513406036142 |
oct | 1605663106647 |
9 | 376383076884 |
10 | 121044241831 |
11 | 473753564a7 |
12 | 1b56157b087 |
13 | b550644a46 |
14 | 5c03ccd059 |
15 | 32369c5821 |
hex | 1c2ecc8da7 |
121044241831 has 2 divisors, whose sum is σ = 121044241832. Its totient is φ = 121044241830.
The previous prime is 121044241793. The next prime is 121044241837. The reversal of 121044241831 is 138142440121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121044241831 - 29 = 121044241319 is a prime.
It is a super-2 number, since 2×1210442418312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121044241793 and 121044241802.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121044241837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60522120915 + 60522120916.
It is an arithmetic number, because the mean of its divisors is an integer number (60522120916).
Almost surely, 2121044241831 is an apocalyptic number.
121044241831 is a deficient number, since it is larger than the sum of its proper divisors (1).
121044241831 is an equidigital number, since it uses as much as digits as its factorization.
121044241831 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 121044241831 its reverse (138142440121), we get a palindrome (259186681952).
The spelling of 121044241831 in words is "one hundred twenty-one billion, forty-four million, two hundred forty-one thousand, eight hundred thirty-one".
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