121100000141 has 2 divisors, whose sum is σ = 121100000142. Its totient is φ = 121100000140.

The previous prime is 121100000113. The next prime is 121100000143. The reversal of 121100000141 is 141000001121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112919521225 + 8180478916 = 336035^2 + 90446^2 .

It is a cyclic number.

It is not a de Polignac number, because 121100000141 - 2¹⁴ = 121099983757 is a prime.

It is a Sophie Germain prime.

Together with 121100000143, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121100000143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550000070 + 60550000071.

It is an arithmetic number, because the mean of its divisors is an integer number (60550000071).

Almost surely, 2^121100000141 is an apocalyptic number.

It is an amenable number.

121100000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

121100000141 is an equidigital number, since it uses as much as digits as its factorization.

121100000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 121100000141 its reverse (141000001121), we get a palindrome (262100001262).

The spelling of 121100000141 in words is "one hundred twenty-one billion, one hundred million, one hundred forty-one", and thus it is an aban number.