12110101613503 has 2 divisors, whose sum is σ = 12110101613504. Its totient is φ = 12110101613502.

The previous prime is 12110101613431. The next prime is 12110101613563. The reversal of 12110101613503 is 30531610101121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12110101613503 is a prime.

It is a super-2 number, since 2×12110101613503² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110101613563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055050806751 + 6055050806752.

It is an arithmetic number, because the mean of its divisors is an integer number (6055050806752).

Almost surely, 2^{12110101613503} is an apocalyptic number.

12110101613503 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110101613503 is an equidigital number, since it uses as much as digits as its factorization.

12110101613503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 25.

Adding to 12110101613503 its reverse (30531610101121), we get a palindrome (42641711714624).

The spelling of 12110101613503 in words is "twelve trillion, one hundred ten billion, one hundred one million, six hundred thirteen thousand, five hundred three".