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1211011320121 is a prime number
BaseRepresentation
bin10001100111110101111…
…001100100100100111001
311021202211110110010111121
4101213311321210210321
5124320122344220441
62324155251225241
7153330663244111
oct21476571444471
94252743403447
101211011320121
11427650356959
121768512a8221
138a275976a45
1442882b04041
152177b763dd1
hex119f5e64939

1211011320121 has 2 divisors, whose sum is σ = 1211011320122. Its totient is φ = 1211011320120.

The previous prime is 1211011320109. The next prime is 1211011320149. The reversal of 1211011320121 is 1210231101121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1047501075625 + 163510244496 = 1023475^2 + 404364^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211011320121 - 27 = 1211011319993 is a prime.

It is a super-2 number, since 2×12110113201212 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211011320095 and 1211011320104.

It is not a weakly prime, because it can be changed into another prime (1211011324121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605505660060 + 605505660061.

It is an arithmetic number, because the mean of its divisors is an integer number (605505660061).

Almost surely, 21211011320121 is an apocalyptic number.

It is an amenable number.

1211011320121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211011320121 is an equidigital number, since it uses as much as digits as its factorization.

1211011320121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 1211011320121 its reverse (1210231101121), we get a palindrome (2421242421242).

The spelling of 1211011320121 in words is "one trillion, two hundred eleven billion, eleven million, three hundred twenty thousand, one hundred twenty-one".