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121101333441037 is a prime number
BaseRepresentation
bin11011100010010000011001…
…111101100010101000001101
3120212210011201010221121220021
4123202100121331202220031
5111333111012330103122
61105321103510422141
734336165636031665
oct3342203175425015
9525704633847807
10121101333441037
113564a872693194
12116ba2bb661951
135275a6454b1c1
1421c949b6811a5
15e001cc2001c7
hex6e2419f62a0d

121101333441037 has 2 divisors, whose sum is σ = 121101333441038. Its totient is φ = 121101333441036.

The previous prime is 121101333440963. The next prime is 121101333441073. The reversal of 121101333441037 is 730144333101121.

Together with next prime (121101333441073) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86260516823716 + 34840816617321 = 9287654^2 + 5902611^2 .

It is a cyclic number.

It is not a de Polignac number, because 121101333441037 - 27 = 121101333440909 is a prime.

It is a super-2 number, since 2×1211013334410372 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121101333440993 and 121101333441011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121101333441337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550666720518 + 60550666720519.

It is an arithmetic number, because the mean of its divisors is an integer number (60550666720519).

Almost surely, 2121101333441037 is an apocalyptic number.

It is an amenable number.

121101333441037 is a deficient number, since it is larger than the sum of its proper divisors (1).

121101333441037 is an equidigital number, since it uses as much as digits as its factorization.

121101333441037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 34.

Adding to 121101333441037 its reverse (730144333101121), we get a palindrome (851245666542158).

The spelling of 121101333441037 in words is "one hundred twenty-one trillion, one hundred one billion, three hundred thirty-three million, four hundred forty-one thousand, thirty-seven".