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121102112102119 is a prime number
BaseRepresentation
bin11011100010010001001000…
…010111111001011011100111
3120212210020201102010201002121
4123202101020113321123213
5111333114111144231434
61105321313044050411
734336224142401631
oct3342211027713347
9525706642121077
10121102112102119
1135650132179845
12116ba498393a07
135275b5996c3c5
1421c9532c53a51
15e0022575e7b4
hex6e24485f96e7

121102112102119 has 2 divisors, whose sum is σ = 121102112102120. Its totient is φ = 121102112102118.

The previous prime is 121102112102087. The next prime is 121102112102131. The reversal of 121102112102119 is 911201211201121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121102112102119 - 25 = 121102112102087 is a prime.

It is a super-2 number, since 2×1211021121021192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121102112102093 and 121102112102102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121102112102519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551056051059 + 60551056051060.

It is an arithmetic number, because the mean of its divisors is an integer number (60551056051060).

Almost surely, 2121102112102119 is an apocalyptic number.

121102112102119 is a deficient number, since it is larger than the sum of its proper divisors (1).

121102112102119 is an equidigital number, since it uses as much as digits as its factorization.

121102112102119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 25.

The spelling of 121102112102119 in words is "one hundred twenty-one trillion, one hundred two billion, one hundred twelve million, one hundred two thousand, one hundred nineteen".