Base | Representation |
---|---|
bin | 10110100011101010… |
… | …01011011110111111 |
3 | 1011020222200122220012 |
4 | 23101311023132333 |
5 | 144300220012112 |
6 | 5321410013435 |
7 | 606050652113 |
oct | 132165133677 |
9 | 34228618805 |
10 | 12110313407 |
11 | 5154a57785 |
12 | 241b87727b |
13 | 11acc7972a |
14 | 82c535743 |
15 | 4ad2b1022 |
hex | 2d1d4b7bf |
12110313407 has 2 divisors, whose sum is σ = 12110313408. Its totient is φ = 12110313406.
The previous prime is 12110313403. The next prime is 12110313497. The reversal of 12110313407 is 70431301121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110313407 - 22 = 12110313403 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110313403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055156703 + 6055156704.
It is an arithmetic number, because the mean of its divisors is an integer number (6055156704).
Almost surely, 212110313407 is an apocalyptic number.
12110313407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110313407 is an equidigital number, since it uses as much as digits as its factorization.
12110313407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 12110313407 its reverse (70431301121), we get a palindrome (82541614528).
The spelling of 12110313407 in words is "twelve billion, one hundred ten million, three hundred thirteen thousand, four hundred seven".
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