121103143020 has 144 divisors (see below), whose sum is σ = 371429997120. Its totient is φ = 31935936000.

The previous prime is 121103143013. The next prime is 121103143033. The reversal of 121103143020 is 20341301121.

121103143020 is a `hidden beast` number, since 1 + 211 + 0 + 3 + 1 + 430 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 121103142984 and 121103143002.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17103841 + ... + 17110919.

It is an arithmetic number, because the mean of its divisors is an integer number (2579374980).

Almost surely, 2^121103143020 is an apocalyptic number.

121103143020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121103143020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (185714998560).

121103143020 is an abundant number, since it is smaller than the sum of its proper divisors (250326854100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121103143020 is a wasteful number, since it uses less digits than its factorization.

121103143020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8136 (or 8131 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 121103143020 its reverse (20341301121), we get a palindrome (141444444141).

The spelling of 121103143020 in words is "one hundred twenty-one billion, one hundred three million, one hundred forty-three thousand, twenty".