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12111000870049 is a prime number
BaseRepresentation
bin1011000000111100111111…
…1001111001110010100001
31120212210121110210112202121
42300033033321321302201
53041411312210320144
641431414511544241
72356663614566314
oct260171771716241
946783543715677
1012111000870049
11394a279292444
12143723982b081
1369b0a736c993
142dc265a9897b
1516007cd1c384
hexb03cfe79ca1

12111000870049 has 2 divisors, whose sum is σ = 12111000870050. Its totient is φ = 12111000870048.

The previous prime is 12111000870047. The next prime is 12111000870061. The reversal of 12111000870049 is 94007800011121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11731721025600 + 379279844449 = 3425160^2 + 615857^2 .

It is a cyclic number.

It is not a de Polignac number, because 12111000870049 - 21 = 12111000870047 is a prime.

It is a super-3 number, since 3×121110008700493 (a number of 40 digits) contains 333 as substring.

Together with 12111000870047, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12111000869996 and 12111000870023.

It is not a weakly prime, because it can be changed into another prime (12111000870047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055500435024 + 6055500435025.

It is an arithmetic number, because the mean of its divisors is an integer number (6055500435025).

Almost surely, 212111000870049 is an apocalyptic number.

It is an amenable number.

12111000870049 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111000870049 is an equidigital number, since it uses as much as digits as its factorization.

12111000870049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 34.

The spelling of 12111000870049 in words is "twelve trillion, one hundred eleven billion, eight hundred seventy thousand, forty-nine".