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12111003433 is a prime number
BaseRepresentation
bin10110100011101111…
…10011111100101001
31011021000222201102201
423101313303330221
5144300404102213
65321432500201
7606056554624
oct132167637451
934230881381
1012111003433
115155389151
12241bb4a661
1311b015b829
1482c674dbb
154ad39a6dd
hex2d1df3f29

12111003433 has 2 divisors, whose sum is σ = 12111003434. Its totient is φ = 12111003432.

The previous prime is 12111003431. The next prime is 12111003451. The reversal of 12111003433 is 33430011121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11860952464 + 250050969 = 108908^2 + 15813^2 .

It is a cyclic number.

It is not a de Polignac number, because 12111003433 - 21 = 12111003431 is a prime.

Together with 12111003431, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 12111003433.

It is not a weakly prime, because it can be changed into another prime (12111003431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055501716 + 6055501717.

It is an arithmetic number, because the mean of its divisors is an integer number (6055501717).

Almost surely, 212111003433 is an apocalyptic number.

It is an amenable number.

12111003433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111003433 is an equidigital number, since it uses as much as digits as its factorization.

12111003433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12111003433 its reverse (33430011121), we get a palindrome (45541014554).

The spelling of 12111003433 in words is "twelve billion, one hundred eleven million, three thousand, four hundred thirty-three".