12111003431 has 2 divisors, whose sum is σ = 12111003432. Its totient is φ = 12111003430.

The previous prime is 12111003413. The next prime is 12111003433. The reversal of 12111003431 is 13430011121.

Together with previous prime (12111003413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12111003431 is a prime.

It is a super-2 number, since 2×12111003431² (a number of 21 digits) contains 22 as substring.

Together with 12111003433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12111003433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055501715 + 6055501716.

It is an arithmetic number, because the mean of its divisors is an integer number (6055501716).

Almost surely, 2^12111003431 is an apocalyptic number.

12111003431 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111003431 is an equidigital number, since it uses as much as digits as its factorization.

12111003431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12111003431 its reverse (13430011121), we get a palindrome (25541014552).

The spelling of 12111003431 in words is "twelve billion, one hundred eleven million, three thousand, four hundred thirty-one".