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1211102019943 is a prime number
BaseRepresentation
bin10001100111111011010…
…011100100000101100111
311021210001210010011021021
4101213323103210011213
5124320314104114233
62324212251232011
7153333144213064
oct21477323440547
94253053104237
101211102019943
11427697575a92
12176877748607
138a28b6b238a
1442890b93c6b
15217846cce2d
hex119fb4e4167

1211102019943 has 2 divisors, whose sum is σ = 1211102019944. Its totient is φ = 1211102019942.

The previous prime is 1211102019863. The next prime is 1211102020031. The reversal of 1211102019943 is 3499102011121.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1211102019943 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1211102019899 and 1211102019908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211102019143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605551009971 + 605551009972.

It is an arithmetic number, because the mean of its divisors is an integer number (605551009972).

Almost surely, 21211102019943 is an apocalyptic number.

1211102019943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211102019943 is an equidigital number, since it uses as much as digits as its factorization.

1211102019943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 34.

The spelling of 1211102019943 in words is "one trillion, two hundred eleven billion, one hundred two million, nineteen thousand, nine hundred forty-three".