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12111211001173 is a prime number
BaseRepresentation
bin1011000000111101110001…
…1011011111010101010101
31120212211011010012022110211
42300033130123133111111
53041412230004014143
641431451415445421
72360002045640434
oct260173433372525
946784133168424
1012111211001173
11394a376965029
121437298086871
1369b10ba6341b
142dc28595711b
151600914c849d
hexb03dc6df555

12111211001173 has 2 divisors, whose sum is σ = 12111211001174. Its totient is φ = 12111211001172.

The previous prime is 12111211001171. The next prime is 12111211001203. The reversal of 12111211001173 is 37110011211121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7683751153764 + 4427459847409 = 2771958^2 + 2104153^2 .

It is an emirp because it is prime and its reverse (37110011211121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12111211001173 - 21 = 12111211001171 is a prime.

Together with 12111211001171, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12111211001171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055605500586 + 6055605500587.

It is an arithmetic number, because the mean of its divisors is an integer number (6055605500587).

Almost surely, 212111211001173 is an apocalyptic number.

It is an amenable number.

12111211001173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111211001173 is an equidigital number, since it uses as much as digits as its factorization.

12111211001173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 22.

Adding to 12111211001173 its reverse (37110011211121), we get a palindrome (49221222212294).

The spelling of 12111211001173 in words is "twelve trillion, one hundred eleven billion, two hundred eleven million, one thousand, one hundred seventy-three".