Search a number
-
+
121112201202037 is a prime number
BaseRepresentation
bin11011100010011010100001…
…101110110000100101110101
3120212211012202112120002022221
4123202122201232300211311
5111333300242001431122
61105330102132322341
734340032151340253
oct3342324156604565
9525735675502287
10121112201202037
113565443a20a951
12117004331733b1
135276aa6c54c06
1421c9c0cb6b5d3
15e0061636c6c7
hex6e26a1bb0975

121112201202037 has 2 divisors, whose sum is σ = 121112201202038. Its totient is φ = 121112201202036.

The previous prime is 121112201202011. The next prime is 121112201202173. The reversal of 121112201202037 is 730202102211121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77525189815921 + 43587011386116 = 8804839^2 + 6602046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121112201202037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121112201502037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556100601018 + 60556100601019.

It is an arithmetic number, because the mean of its divisors is an integer number (60556100601019).

Almost surely, 2121112201202037 is an apocalyptic number.

It is an amenable number.

121112201202037 is a deficient number, since it is larger than the sum of its proper divisors (1).

121112201202037 is an equidigital number, since it uses as much as digits as its factorization.

121112201202037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 121112201202037 its reverse (730202102211121), we get a palindrome (851314303413158).

The spelling of 121112201202037 in words is "one hundred twenty-one trillion, one hundred twelve billion, two hundred one million, two hundred two thousand, thirty-seven".