12111302130000 has 400 divisors, whose sum is σ = 40442960859840. Its totient is φ = 3119745024000.

The previous prime is 12111302129981. The next prime is 12111302130041. The reversal of 12111302130000 is 3120311121.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 154250752 + ... + 154329248.

Almost surely, 2^{12111302130000} is an apocalyptic number.

12111302130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12111302130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20221480429920).

12111302130000 is an abundant number, since it is smaller than the sum of its proper divisors (28331658729840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12111302130000 is a wasteful number, since it uses less digits than its factorization.

12111302130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78704 (or 78683 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 12111302130000 its reverse (3120311121), we get a palindrome (12114422441121).

The spelling of 12111302130000 in words is "twelve trillion, one hundred eleven billion, three hundred two million, one hundred thirty thousand".