Base | Representation |
---|---|
bin | 11011100010011011010011… |
… | …001101010111101010101111 |
3 | 120212211021220101112221101021 |
4 | 123202123103031113222233 |
5 | 111333303442003404444 |
6 | 1105330320344355011 |
7 | 34340061551212141 |
oct | 3342332315275257 |
9 | 525737811487337 |
10 | 121113031309999 |
11 | 35654825845293 |
12 | 11700625175a67 |
13 | 5276ba9c19c61 |
14 | 21c9c8b0d2c91 |
15 | e00664190584 |
hex | 6e26d3357aaf |
121113031309999 has 2 divisors, whose sum is σ = 121113031310000. Its totient is φ = 121113031309998.
The previous prime is 121113031309997. The next prime is 121113031310009. The reversal of 121113031309999 is 999903130311121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121113031309999 - 21 = 121113031309997 is a prime.
Together with 121113031309997, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121113031309997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556515654999 + 60556515655000.
It is an arithmetic number, because the mean of its divisors is an integer number (60556515655000).
Almost surely, 2121113031309999 is an apocalyptic number.
121113031309999 is a deficient number, since it is larger than the sum of its proper divisors (1).
121113031309999 is an equidigital number, since it uses as much as digits as its factorization.
121113031309999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 354294, while the sum is 52.
The spelling of 121113031309999 in words is "one hundred twenty-one trillion, one hundred thirteen billion, thirty-one million, three hundred nine thousand, nine hundred ninety-nine".
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