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121113202030 = 2512111320203
BaseRepresentation
bin111000011001011101…
…0001100110101101110
3102120121120212010121021
41300302322030311232
53441014434431110
6131345540124354
711515204142242
oct1606272146556
9376546763537
10121113202030
11474002772a7
121b5806966ba
13b561a0b1b2
145c0d120422
15323ca982da
hex1c32e8cd6e

121113202030 has 8 divisors (see below), whose sum is σ = 218003763672. Its totient is φ = 48445280808.

The previous prime is 121113202013. The next prime is 121113202057. The reversal of 121113202030 is 30202311121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1211132020302 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121113201995 and 121113202013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6055660092 + ... + 6055660111.

It is an arithmetic number, because the mean of its divisors is an integer number (27250470459).

Almost surely, 2121113202030 is an apocalyptic number.

121113202030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

121113202030 is a deficient number, since it is larger than the sum of its proper divisors (96890561642).

121113202030 is a wasteful number, since it uses less digits than its factorization.

121113202030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12111320210.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 121113202030 its reverse (30202311121), we get a palindrome (151315513151).

The spelling of 121113202030 in words is "one hundred twenty-one billion, one hundred thirteen million, two hundred two thousand, thirty".

Divisors: 1 2 5 10 12111320203 24222640406 60556601015 121113202030