Base | Representation |
---|---|
bin | 111000011001011101… |
… | …0001100110110110111 |
3 | 102120121120212010200222 |
4 | 1300302322030312313 |
5 | 3441014434431403 |
6 | 131345540124555 |
7 | 11515204142405 |
oct | 1606272146667 |
9 | 376546763628 |
10 | 121113202103 |
11 | 47400277363 |
12 | 1b58069675b |
13 | b561a0b23a |
14 | 5c0d120475 |
15 | 323ca98338 |
hex | 1c32e8cdb7 |
121113202103 has 2 divisors, whose sum is σ = 121113202104. Its totient is φ = 121113202102.
The previous prime is 121113202061. The next prime is 121113202117. The reversal of 121113202103 is 301202311121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121113202103 - 212 = 121113198007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121113202123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556601051 + 60556601052.
It is an arithmetic number, because the mean of its divisors is an integer number (60556601052).
Almost surely, 2121113202103 is an apocalyptic number.
121113202103 is a deficient number, since it is larger than the sum of its proper divisors (1).
121113202103 is an equidigital number, since it uses as much as digits as its factorization.
121113202103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 121113202103 its reverse (301202311121), we get a palindrome (422315513224).
The spelling of 121113202103 in words is "one hundred twenty-one billion, one hundred thirteen million, two hundred two thousand, one hundred three".
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