Base | Representation |
---|---|
bin | 1011000000111110001110… |
… | …0101101101101110110100 |
3 | 1120212211110111020002102001 |
4 | 2300033203211231232310 |
5 | 3041413001231401400 |
6 | 41431511350225044 |
7 | 2360005034644300 |
oct | 260174345555664 |
9 | 46784414202361 |
10 | 12111331122100 |
11 | 394a428749721 |
12 | 1437310355184 |
13 | 69b12a9003b2 |
14 | 2dc2978a4d00 |
15 | 16009bd04a6a |
hex | b03e396dbb4 |
12111331122100 has 54 divisors (see below), whose sum is σ = 30572460144870. Its totient is φ = 4152456383040.
The previous prime is 12111331122083. The next prime is 12111331122113. The reversal of 12111331122100 is 122113311121.
It can be written as a sum of positive squares in 3 ways, for example, as 4048127904016 + 8063203218084 = 2011996^2 + 2839578^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 1235845215 + ... + 1235855014.
Almost surely, 212111331122100 is an apocalyptic number.
12111331122100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12111331122100 is an abundant number, since it is smaller than the sum of its proper divisors (18461129022770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12111331122100 is a wasteful number, since it uses less digits than its factorization.
12111331122100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2471700257 (or 2471700243 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 12111331122100 its reverse (122113311121), we get a palindrome (12233444433221).
The spelling of 12111331122100 in words is "twelve trillion, one hundred eleven billion, three hundred thirty-one million, one hundred twenty-two thousand, one hundred".
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