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121115101981 is a prime number
BaseRepresentation
bin111000011001100000…
…1011100101100011101
3102120121201102122211211
41300303001130230131
53441020431230411
6131350044544421
711515226244406
oct1606301345435
9376551378754
10121115101981
1147401354805
121b581252111
13b562224c23
145c0d4969ad
15323cd21221
hex1c3305cb1d

121115101981 has 2 divisors, whose sum is σ = 121115101982. Its totient is φ = 121115101980.

The previous prime is 121115101979. The next prime is 121115101999. The reversal of 121115101981 is 189101511121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112650181956 + 8464920025 = 335634^2 + 92005^2 .

It is an emirp because it is prime and its reverse (189101511121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121115101981 - 21 = 121115101979 is a prime.

It is a super-2 number, since 2×1211151019812 (a number of 23 digits) contains 22 as substring.

Together with 121115101979, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121115101381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60557550990 + 60557550991.

It is an arithmetic number, because the mean of its divisors is an integer number (60557550991).

Almost surely, 2121115101981 is an apocalyptic number.

It is an amenable number.

121115101981 is a deficient number, since it is larger than the sum of its proper divisors (1).

121115101981 is an equidigital number, since it uses as much as digits as its factorization.

121115101981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 31.

The spelling of 121115101981 in words is "one hundred twenty-one billion, one hundred fifteen million, one hundred one thousand, nine hundred eighty-one".