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121120101011220 = 223531536793719571
BaseRepresentation
bin11011100010100001111000…
…100110001000111100010100
3120212211222011002102222021020
4123202201320212020330110
5111333412431324324340
61105333450052521140
734340432004532023
oct3342417046107424
9525758132388236
10121120101011220
1135657823476473
1211701a789201b0
1352777657b870c
1421ca35bdd48ba
15e00929b769d0
hex6e2878988f14

121120101011220 has 384 divisors, whose sum is σ = 362409837576192. Its totient is φ = 30175549747200.

The previous prime is 121120101011159. The next prime is 121120101011249. The reversal of 121120101011220 is 22110101021121.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 121120101011220.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 6188744035 + ... + 6188763605.

It is an arithmetic number, because the mean of its divisors is an integer number (943775618688).

Almost surely, 2121120101011220 is an apocalyptic number.

121120101011220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121120101011220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (181204918788096).

121120101011220 is an abundant number, since it is smaller than the sum of its proper divisors (241289736564972).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121120101011220 is a wasteful number, since it uses less digits than its factorization.

121120101011220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20671 (or 20669 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 121120101011220 its reverse (22110101021121), we get a palindrome (143230202032341).

Subtracting from 121120101011220 its reverse (22110101021121), we obtain a palindrome (99009999990099).

The spelling of 121120101011220 in words is "one hundred twenty-one trillion, one hundred twenty billion, one hundred one million, eleven thousand, two hundred twenty".