Base | Representation |
---|---|
bin | 10001101000000001010… |
… | …100110110011010001111 |
3 | 11021210022211011111220002 |
4 | 101220001110312122033 |
5 | 124321020433123211 |
6 | 2324230300114515 |
7 | 153335511543125 |
oct | 21500124663217 |
9 | 4253284144802 |
10 | 1211203020431 |
11 | 427739590168 |
12 | 1768a5535a3b |
13 | 8a2a65b6391 |
14 | 428a0365915 |
15 | 2178d4ce03b |
hex | 11a0153668f |
1211203020431 has 2 divisors, whose sum is σ = 1211203020432. Its totient is φ = 1211203020430.
The previous prime is 1211203020421. The next prime is 1211203020491. The reversal of 1211203020431 is 1340203021121.
It is a weak prime.
It is an emirp because it is prime and its reverse (1340203021121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211203020431 - 210 = 1211203019407 is a prime.
It is a super-2 number, since 2×12112030204312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211203020421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605601510215 + 605601510216.
It is an arithmetic number, because the mean of its divisors is an integer number (605601510216).
Almost surely, 21211203020431 is an apocalyptic number.
1211203020431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211203020431 is an equidigital number, since it uses as much as digits as its factorization.
1211203020431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1211203020431 its reverse (1340203021121), we get a palindrome (2551406041552).
The spelling of 1211203020431 in words is "one trillion, two hundred eleven billion, two hundred three million, twenty thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •