1340203021121 has 2 divisors, whose sum is σ = 1340203021122. Its totient is φ = 1340203021120.

The previous prime is 1340203021111. The next prime is 1340203021123. The reversal of 1340203021121 is 1211203020431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1296321150721 + 43881870400 = 1138561^2 + 209480^2 .

It is an emirp because it is prime and its reverse (1211203020431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340203021121 - 2⁶ = 1340203021057 is a prime.

It is a super-2 number, since 2×1340203021121² (a number of 25 digits) contains 22 as substring.

Together with 1340203021123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340203021093 and 1340203021102.

It is not a weakly prime, because it can be changed into another prime (1340203021123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670101510560 + 670101510561.

It is an arithmetic number, because the mean of its divisors is an integer number (670101510561).

Almost surely, 2^{1340203021121} is an apocalyptic number.

It is an amenable number.

1340203021121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340203021121 is an equidigital number, since it uses as much as digits as its factorization.

1340203021121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1340203021121 its reverse (1211203020431), we get a palindrome (2551406041552).

The spelling of 1340203021121 in words is "one trillion, three hundred forty billion, two hundred three million, twenty-one thousand, one hundred twenty-one".