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12112110219173 is a prime number
BaseRepresentation
bin1011000001000001001000…
…0001101110111110100101
31120212220110210020022200012
42300100102001232332211
53041421100204003143
641432120541100005
72360033245111316
oct260202201567645
946786423208605
1012112110219173
11394a7985028a8
1214374a9257605
1369b223144b93
142dc32d14c60d
151600e53ed418
hexb041206efa5

12112110219173 has 2 divisors, whose sum is σ = 12112110219174. Its totient is φ = 12112110219172.

The previous prime is 12112110219133. The next prime is 12112110219191. The reversal of 12112110219173 is 37191201121121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9106193416609 + 3005916802564 = 3017647^2 + 1733758^2 .

It is a cyclic number.

It is not a de Polignac number, because 12112110219173 - 220 = 12112109170597 is a prime.

It is a super-2 number, since 2×121121102191732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12112110219133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056055109586 + 6056055109587.

It is an arithmetic number, because the mean of its divisors is an integer number (6056055109587).

Almost surely, 212112110219173 is an apocalyptic number.

It is an amenable number.

12112110219173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12112110219173 is an equidigital number, since it uses as much as digits as its factorization.

12112110219173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 32.

The spelling of 12112110219173 in words is "twelve trillion, one hundred twelve billion, one hundred ten million, two hundred nineteen thousand, one hundred seventy-three".