Base | Representation |
---|---|
bin | 1011000001000001001000… |
… | …1000111100101001100111 |
3 | 1120212220110220210101122121 |
4 | 2300100102020330221213 |
5 | 3041421101200011213 |
6 | 41432121045410411 |
7 | 2360033300145421 |
oct | 260202210745147 |
9 | 46786426711577 |
10 | 12112112110183 |
11 | 394a799584618 |
12 | 14374a9a09a07 |
13 | 69b223657817 |
14 | 2dc32d4c1811 |
15 | 1600e567388d |
hex | b041223ca67 |
12112112110183 has 2 divisors, whose sum is σ = 12112112110184. Its totient is φ = 12112112110182.
The previous prime is 12112112110177. The next prime is 12112112110237. The reversal of 12112112110183 is 38101121121121.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12112112110183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12112112119183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056056055091 + 6056056055092.
It is an arithmetic number, because the mean of its divisors is an integer number (6056056055092).
Almost surely, 212112112110183 is an apocalyptic number.
12112112110183 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112112110183 is an equidigital number, since it uses as much as digits as its factorization.
12112112110183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 25.
The spelling of 12112112110183 in words is "twelve trillion, one hundred twelve billion, one hundred twelve million, one hundred ten thousand, one hundred eighty-three".
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