Base | Representation |
---|---|
bin | 11011100010100011110111… |
… | …101100010010111001000111 |
3 | 120212212011122200210001110221 |
4 | 123202203313230102321013 |
5 | 111333431313213100041 |
6 | 1105334441423525211 |
7 | 34340535566126404 |
oct | 3342436754227107 |
9 | 525764580701427 |
10 | 121122233331271 |
11 | 3565871807a047 |
12 | 11702372a59807 |
13 | 5277a154b1563 |
14 | 21ca4c12952ab |
15 | e00a01e752d1 |
hex | 6e28f7b12e47 |
121122233331271 has 2 divisors, whose sum is σ = 121122233331272. Its totient is φ = 121122233331270.
The previous prime is 121122233331259. The next prime is 121122233331299. The reversal of 121122233331271 is 172133332221121.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121122233331271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121122233361271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561116665635 + 60561116665636.
It is an arithmetic number, because the mean of its divisors is an integer number (60561116665636).
Almost surely, 2121122233331271 is an apocalyptic number.
121122233331271 is a deficient number, since it is larger than the sum of its proper divisors (1).
121122233331271 is an equidigital number, since it uses as much as digits as its factorization.
121122233331271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18144, while the sum is 34.
Adding to 121122233331271 its reverse (172133332221121), we get a palindrome (293255565552392).
The spelling of 121122233331271 in words is "one hundred twenty-one trillion, one hundred twenty-two billion, two hundred thirty-three million, three hundred thirty-one thousand, two hundred seventy-one".
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