Base | Representation |
---|---|
bin | 1011000001000001111000… |
… | …0000100010011000001101 |
3 | 1120212220222210110211110012 |
4 | 2300100132000202120031 |
5 | 3041422003133411023 |
6 | 41432152521323005 |
7 | 2360041235514506 |
oct | 260203600423015 |
9 | 46786883424405 |
10 | 12112311232013 |
11 | 394a890a17813 |
12 | 1437544636465 |
13 | 69b2559951a5 |
14 | 2dc34bb15bad |
15 | 160107da7978 |
hex | b041e02260d |
12112311232013 has 2 divisors, whose sum is σ = 12112311232014. Its totient is φ = 12112311232012.
The previous prime is 12112311232009. The next prime is 12112311232031. The reversal of 12112311232013 is 31023211321121.
It is a happy number.
Together with next prime (12112311232031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7119061776649 + 4993249455364 = 2668157^2 + 2234558^2 .
It is a cyclic number.
It is not a de Polignac number, because 12112311232013 - 22 = 12112311232009 is a prime.
It is a super-2 number, since 2×121123112320132 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12112311232013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12112311232313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056155616006 + 6056155616007.
It is an arithmetic number, because the mean of its divisors is an integer number (6056155616007).
Almost surely, 212112311232013 is an apocalyptic number.
It is an amenable number.
12112311232013 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112311232013 is an equidigital number, since it uses as much as digits as its factorization.
12112311232013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 12112311232013 its reverse (31023211321121), we get a palindrome (43135522553134).
The spelling of 12112311232013 in words is "twelve trillion, one hundred twelve billion, three hundred eleven million, two hundred thirty-two thousand, thirteen".
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