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121126446545051 is a prime number
BaseRepresentation
bin11011100010100111110010…
…110100011011100010011011
3120212212120112022200111020202
4123202213302310123202123
5111334013430303420201
61105340415451412415
734341045155633453
oct3342476264334233
9525776468614222
10121126446545051
113565a48a350a02
1211703149a5410b
13527823733586c
1421ca7a0a6ad63
15e00b9bcb4c6b
hex6e29f2d1b89b

121126446545051 has 2 divisors, whose sum is σ = 121126446545052. Its totient is φ = 121126446545050.

The previous prime is 121126446545003. The next prime is 121126446545053. The reversal of 121126446545051 is 150545644621121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121126446545051 - 214 = 121126446528667 is a prime.

Together with 121126446545053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121126446544987 and 121126446545005.

It is not a weakly prime, because it can be changed into another prime (121126446545053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60563223272525 + 60563223272526.

It is an arithmetic number, because the mean of its divisors is an integer number (60563223272526).

Almost surely, 2121126446545051 is an apocalyptic number.

121126446545051 is a deficient number, since it is larger than the sum of its proper divisors (1).

121126446545051 is an equidigital number, since it uses as much as digits as its factorization.

121126446545051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152000, while the sum is 47.

The spelling of 121126446545051 in words is "one hundred twenty-one trillion, one hundred twenty-six billion, four hundred forty-six million, five hundred forty-five thousand, fifty-one".